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[improve][misc] Add LongArrayAckSets for allocation-free ack set operations #26128
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5951c36
[improve][common] Add cardinality helpers for bitset words
Shawyeok 7ec3f9c
[improve][common] Introduce AckSetUtil for allocation-free ack-set wo…
Shawyeok 3667187
Address review: trim trailing zero words in intersect, revert isAckSe…
Shawyeok 4ad88cd
Address review: rename AckSetUtil to LongArrayAckSets
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81 changes: 81 additions & 0 deletions
81
pulsar-common/src/main/java/org/apache/pulsar/common/util/AckSetUtil.java
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,81 @@ | ||
| /* | ||
| * Licensed to the Apache Software Foundation (ASF) under one | ||
| * or more contributor license agreements. See the NOTICE file | ||
| * distributed with this work for additional information | ||
| * regarding copyright ownership. The ASF licenses this file | ||
| * to you under the Apache License, Version 2.0 (the | ||
| * "License"); you may not use this file except in compliance | ||
| * with the License. You may obtain a copy of the License at | ||
| * | ||
| * http://www.apache.org/licenses/LICENSE-2.0 | ||
| * | ||
| * Unless required by applicable law or agreed to in writing, | ||
| * software distributed under the License is distributed on an | ||
| * "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY | ||
| * KIND, either express or implied. See the License for the | ||
| * specific language governing permissions and limitations | ||
| * under the License. | ||
| */ | ||
| package org.apache.pulsar.common.util; | ||
|
|
||
| /** | ||
| * Utility methods for operating on ack-set word arrays without allocating a {@code BitSet} instance. | ||
| */ | ||
| public class AckSetUtil { | ||
|
|
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| /** | ||
| * Returns the number of bits set to {@code true} in the given words. | ||
| * | ||
| * @param words a long array containing a little-endian representation of a sequence of bits | ||
| * @return the number of bits set to {@code true} | ||
| */ | ||
| public static int cardinality(long[] words) { | ||
|
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| int sum = 0; | ||
| for (long word : words) { | ||
| sum += Long.bitCount(word); | ||
| } | ||
| return sum; | ||
| } | ||
|
|
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| /** | ||
| * Returns a new word array whose elements are the bitwise AND of the corresponding elements of the two inputs. | ||
| * | ||
| * <p>Extra words in the longer array are implicitly ANDed with zero and therefore contribute no set bits. | ||
| * Trailing all-zero words are trimmed from the result, so it is in the same canonical form produced by | ||
| * {@link java.util.BitSet#toLongArray()}. | ||
| * | ||
| * @param set1 a long array containing a little-endian representation of a sequence of bits | ||
| * @param set2 a long array containing a little-endian representation of a sequence of bits | ||
| * @return a new array representing the intersection of the two bit sets, with trailing zero words trimmed | ||
| */ | ||
| public static long[] intersect(long[] set1, long[] set2) { | ||
|
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| int len = Math.min(set1.length, set2.length); | ||
| while (len > 0 && (set1[len - 1] & set2[len - 1]) == 0) { | ||
| len--; | ||
| } | ||
| long[] result = new long[len]; | ||
| for (int i = 0; i < len; i++) { | ||
| result[i] = set1[i] & set2[i]; | ||
| } | ||
| return result; | ||
| } | ||
|
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| /** | ||
| * Returns the number of bits set to {@code true} after applying a logical <b>AND</b> to the given words. | ||
| * | ||
| * <p>When the arrays differ in length, extra words in the longer array are treated as zero (i.e. the AND | ||
| * result for those positions is zero and contributes nothing to the cardinality). | ||
| * | ||
| * @param set1 a long array containing a little-endian representation of a sequence of bits | ||
| * @param set2 a long array containing a little-endian representation of a sequence of bits | ||
| * @return the number of bits set to {@code true} in {@code set1 & set2} | ||
| */ | ||
| public static int cardinalityOfIntersection(long[] set1, long[] set2) { | ||
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| int sum = 0; | ||
| int len = Math.min(set1.length, set2.length); | ||
| for (int i = 0; i < len; i++) { | ||
| sum += Long.bitCount(set1[i] & set2[i]); | ||
| } | ||
| return sum; | ||
| } | ||
| } | ||
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