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The `Ord` trait does not, in fact, require that values of its implementor type form a total order. A weak order is enough, which includes poker cards.
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Co-Authored-By: Claude Fable 5.1 <noreply@anthropic.com>
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The
Ordtrait does not, in fact, require that values of itsimplementor type form a total order. A weak order is enough, which
includes poker cards.
Forum topic:
https://forum.exercism.org/t/technically-inaccurate-slightly-unhelpful-hint-on-the-poker-exercise-on-the-rust-track/72898